导图社区 Amines
Amines思维导图,包括:Chemistry、Heterocyclic ammines、Amine synthesis、Ammine's reaction四部分内容。
编辑于2022-06-12 20:55:41Amines
Chemistry
Nucleophilicity/Basidity
The lewis unshared pair do exist。。
Alkyl ammine is most basic
entire deprotonates in physiologic PH 7.3
pi synstem will delocalize the long pair
decrease in
Nucleophilicity
Basidity
but pyridine carbon is more basic than pyrole
more N on 1 heterocycle further reduce basidity
electron withdrawing groups on aromatic ring further weaken the basidity
-F, -Cl, -Br, -I
-NO2, -CN, -CHO, -CN, -CO2R, -COR, -CO2H
electron donating groups further increase the basidity
-CH3, -OCH3, -OH, -NH2
the amide is less basic than amine due to the longpair is attracted and delocalized by oxygen
stereochemistry
pyramidal inversion
barrier only 25kj/mol
Heterocyclic ammines
Compounds contain one or more nirtogen atoms
Chemistry
saturated heterocycles have similar chemistry as their open chained analogs
Unsaturated aromatic heterocycles
pyrrole
5 membered ring
long pair is part of pi system
not basic at all
C2 derivating electrophilic substitution
imidazole
pyridine
6 membered ring
long pair not part of pi system
basic but less than normal alkyl amine
C3 derivating electrophilic substitution
but not reactive
long pair interfer
N inductive effect
no friedel-crafts reactions
no nitration
pyrimidine
fused ring heterocycles
quinoline
isoquinoline
indole
purine
very stable
undergo
aromatic elctrophilic substitution
Halogenation, nitration, sulfonation, and friedel-crafts acylation
derivative effect look at the stability of intermediate cation
Amine synthesis
Aryl ammine
nitrition of an aromatic ring followed by reduction.
H2, Pt or Fe, H3O+
Alkyl ammine
SN2 reaction of ammonia or an amine with an alkyl halide
Reductive methods
LiAH4 reduction of amides and nitriles
Reductive amination
aldehyde or ketone is treated with amine in the presence of a reducing agent NaBH4
Ammine's reaction
Alkylation
SN2 reaction with alkyl halides
ammonia+ RX---primary ammine+ RX----secondary ammine+ RX----tertiray ammine+ RX-----Quaternary ammonium salt
The problem is: you can't stop
use NaN3 can make it only 1 step, because the azide product is not nucleuphilic, but requires further reduction
nucleophylic acyl substitution with acid chlorides produce amides
usually use pyridine as solvent
Reductive amination
nucleophylic addition with ketone/aldehyde produce Imine/enamines
followed bt reduction by NaBH4 or H2/Ni
NADH in biological system
can accurately produce primary, secondary, tertiary amines
use ammonia, primary amine, secondary amine.
E2 hofmann elimination
produce less highly substituted alkenes
due to steric hinder of the leaving group
they are first quaternized by treatment with idomethane and then heated with silver oxide
excess CH3I converting NH2 into a possitive charge trialkylamine leaving group
3 SN2 reactions
only way to make ammine a better leaving group
bulky, steric hindered
Then E2 happend by a base(typically Ag2O) deprotonate the less hindered carbon
common style in biological system
but only convert ammine into ammonium
Electrophilic Aromatic substitution
amino group is strong activating and ortho- and para- directing
but can't stop at single substitution state, and can't have Friedel crafts reaction
but amide can
so usually Electrophilic aromatic substitusion with amido substituted
mono bromo product because its less basic and less activating